(3y+2)(5y^2+4y-3)=

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Solution for (3y+2)(5y^2+4y-3)= equation:


Simplifying
(3y + 2)(5y2 + 4y + -3) = 0

Reorder the terms:
(2 + 3y)(5y2 + 4y + -3) = 0

Reorder the terms:
(2 + 3y)(-3 + 4y + 5y2) = 0

Multiply (2 + 3y) * (-3 + 4y + 5y2)
(2(-3 + 4y + 5y2) + 3y * (-3 + 4y + 5y2)) = 0
((-3 * 2 + 4y * 2 + 5y2 * 2) + 3y * (-3 + 4y + 5y2)) = 0
((-6 + 8y + 10y2) + 3y * (-3 + 4y + 5y2)) = 0
(-6 + 8y + 10y2 + (-3 * 3y + 4y * 3y + 5y2 * 3y)) = 0
(-6 + 8y + 10y2 + (-9y + 12y2 + 15y3)) = 0

Reorder the terms:
(-6 + 8y + -9y + 10y2 + 12y2 + 15y3) = 0

Combine like terms: 8y + -9y = -1y
(-6 + -1y + 10y2 + 12y2 + 15y3) = 0

Combine like terms: 10y2 + 12y2 = 22y2
(-6 + -1y + 22y2 + 15y3) = 0

Solving
-6 + -1y + 22y2 + 15y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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